> The base potency of LMs is 3C!So we start with a 1 millionth
I calculated it a couple of years ago:
But to be correct, we have to calculate the LM1 like this:
First we have to prepare a trituration of a 3C
1:100x100x100
Second, we dissolve 1 gran (weight is about the same as a drop) in 500
drops.
1:501
Third, we take 1 drop of this LM0, and add 100 drops, and moisten 500
globules with it 1:101:501
So for reaching the LM1 we have a (polished) proportionality to the
mother substance:
1: (100x100x100x500x100x500) =
1: (25x100 e6).
So, an LM1 is - if one is simply measuring the amount - comparable to a
6C.
An LM2 would then be
1: (500x100x25x100 e6)=
1: (125x100 e8)
Which would then be more equivalent to a 9C.
Saying this, please take into account that we use 100(!) succussions
when preparing the LMs, while for the C-potencies only 2 or 10
succussions are used (various pharmacies, different methods).
And: we have not only ONE carrier substance (as in the C's) but 2 - and
in different forms. First the use of alcohol, then the dry globules.
Therefore, no wonder the actions are different.
Best,
Gaby
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Gaby Rottler
Germany
rottler@curantur.de
http://www.curantur.de
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